Torre do Bourbon

distancia 1: 39m

cos.35º=39/H

0.819H=39

H=47,6+1.75=49.35

distancia 2: 33m

cos 40º=37/H

0,707H=37

H=48,3+1.75=50.05

distancia 3: 28m

cos 45=28/h

0,707h=28

H=39,6+1.75=41.35

49.35+50.05+41.35/3=46.91

Poste do Mc Donald's

distancia 1 - 19m:

cos 25º=19/H

0,906H=19

H=54 + 1,75 = 55,75

distancia 2 - 21m:

cos 20º=21/H

0,939H=21

H=22,3 + 1,75 = 24, 05

distancia 3 - 26m:

cos15º= 26/H

o,965H= 26

H=26,9 + 1,75 = 28, 65

55.75+24.05+28.65/3= 36.15

Poste do Bourbon

distancia 1 - 12m:

cos 37º=12/H

o,798H=12

H=15 + 1,75 = 16,75

distancia 2 - 18m:

cos30º=18/H

0,866H=18

H=20 + 1,75 = 21,75

distancia 3 - 24m:

cos 22º=24/H

0,927H=24

H=25 + 1,75 =26,75

16.75+21.75+26.75/3=21.75