Poste do Bourbon

distancia 1 - 12m:

cos 37º=12/H

o,798H=12

H=15 + 1,75 = 16,75

distancia 2 - 18m:

cos30º=18/H

0,866H=18

H=20 + 1,75 = 21,75

distancia 3 - 24m:

cos 22º=24/H

0,927H=24

H=25 + 1,75 =26,75

16.75+21.75+26.75/3=21.75